(w-4)/(16-w^2)

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Solution for (w-4)/(16-w^2) equation: 


D( w )

16-w^2 = 0

16-w^2 = 0

16-w^2 = 0

-1*w^2 = -16 // : -1

w^2 = 16

w^2 = 16 // ^ 1/2

abs(w) = 4

w = 4 or w = -4

w in (-oo:-4) U (-4:4) U (4:+oo)

(w-4)/(16-w^2) = 0

w-4 = 0 // + 4

w = 4

w in { 4} 

w belongs to the empty set

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